Sometimes it's difficult to convert an entire existing class to Kotlin

Who says the entire class has to be converted?

The method is annotated

@kotlin.internal.InlineOnly

. I'm not sure what that implies exactly.

apparently that it can only be inlined, not called directly

Does anybody know the exact semantics around boolean properties on java-sourced objects?

https://kotlinlang.org/docs/reference/java-interop.html#getters-and-setters only specifies "get" and "set" but i suspect "is" is allowable for "get" or something like that

@groostav

public class Test {
    public boolean isSomething() {
        return true;
    }

    public boolean getSomething() {
        return true;
    }

    public void setSomething(boolean s) {
      
    } 
}

val test = Test()
val b = test.isSomething //java: boolean b =  test.isSomething()
val c = test.something //java: boolean c = test.getSomething()
test.isSomething = false //java: test.setSomething(false)
test.something = false //java: test.setSomething(false)

@User uploaded a file: and commented: I'm passing the compatible generics I think, but I still get this error and I don't get what this means. Can someone please explain how to fix this? @yole

@User uploaded a file: and commented: This is the full code

@rakshakhegde can you try using

out Any

instead of

*

?

@debug Nope, still same kinda error

I’m trying to make DSL for OnListChangedCallback. Any other way to do it? @yan

@debug Ok, I got it fixed by changing ObservableList to ObservableArrayList<*>.addOn....

I think the first code didn’t work somehow because ObservableList is an interface(?) But logically even though it is an interface it should be allowed right.. because I could always receive an interface as an argument

I'm not sure, generics is still quite tricky for me and

*

means quite a lot of things

I believe

out Any

would be equivalent to Java's

? extends

out Any

exactly means

? extends Object

in Java

which, I suppose, is exactly the same as

*

@rakshakhegde please do not @mention me unless you're certain that you have a question for me specifically (and no question of the shape "this Kotlin code does not work" matches that criterion)

I think this matches your case

For Foo<T>, where T is an invariant type parameter with the upper bound TUpper, Foo<*> is equivalent to Foo<out TUpper> for reading values and to Foo<in Nothing> for writing values

Alright, sorry, I didn’t get any response from anyone previously.

@debug Alright, I’ll look into this, thanks

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Darn, I'm moving out of london for uni tomorrow 😞

😞 I’m so near but I can’t go 😞

I want Kotlin Night Berlin...! 😄

Manchester is cooler than London

I’ll try to go