that's the java code

while ((res = channel.read(buffer)) > 0) {}

that's probably the only code which can be written shorter in java than in kotlin 🙂

"ugly" workaround

while ({res = channel.read(buffer); res;}() > 0) {

yes. i believe there's a thread somewhere saying that this was intentionally not going to be designed for

you can refactor into a

while (true)

+ `if`/`break` though and it's only 1 more line

ok .. i think i found the thread you mentioned .. i though i just ask .. maybe something changed in kotlin since then 🙂

but thx for your help

This can probably be refactored to a

fold

or

reduce

too

not sure .. fold always returns something like a sequence or? i'd have to use byte[] instead of bytebuffer

i wouldn't know how to rewrite that with fold or reduce ... but i am quite new to kotlin 🙂

Start with a simple Java-like rewrite, using

var

or whatever you’re comfortable with. If it works, I’d stick with it personally.

For bitwise operations I have to use Int.and(Int) right?

Int and Int

?

and

is infix

@jdiaz like

val i: Int = 1 and 2

@jakiej

Oho! I was trying & and I couldnt and then I saw the and method

Even better

Thanks guys

Hi, how can I make

logs.filter { it.appUser != null }.groupBy(Log::appUser)

return Map<String, T> instead of Map<String?, T>?

Maybe

⁠⁠⁠⁠logs.filter { it.appUser != null }.groupBy { it.appUser!! }

?

or it.appUser as String

Thanks both works.

I have a fun which takes a lambda as arg, but sometimes I want to call this fun with no lambda (or empty lambda) what I use now is

val call = <…>
makeCall(call) { }

is it right?

yes. you can also declare an empty lambda as a default argument value:

fun foo(callback: () -> Unit = {})

That's right, problems there. Correct version should be:

class B<T : SomeInterface> : A<T>()

@menegatti, @orangy ^^

hmm

cool