I feel like there's an more concise/elegant way to...

# android

[J6ey]

I feel like there's an more concise/elegant way to write this.

val index = fragmentList.indexOf(fragment)
        fragmentList[index] = NoDataFragment.newInstance()

am I missing something?

[Mihai Potra]

not sure if there is anything better, but you can turn this into a MutableList method and use it as fragmentList.replace(fragment, NoDataFragment.newInstance()) . Something along the line of https://gist.github.com/mpotra/0dddfda9111408bc21041deaccc3c564

[Mihai Potra]

Or use .replaceAll but that iterates over the entire array