Is there any more efficient way of doing this: ```...

# announcements

[dave08]

Is there any more efficient way of doing this:

listOf("cat1-subcat1", "cat1-subcat2", "cat1-subcat3", "cat2-subcat1", "cat2-subcat2")
        .groupBy({ it.split("-")[0] }, { it.split("-")[1] })

?

Result: {cat1=[subcat1, subcat2, subcat3], cat2=[subcat1, subcat2]}