I haven t been able to research my way out of this q hoping kotlinlang #announcements

I haven't been able to research my way out of this...

Ray Deck

10/08/2018, 2:19 PM

I haven't been able to research my way out of this q, hoping the group can help. Is there a way to express a function type with varargs? Like

(varargs T)->T

So that an instance of that type could express in a lambda as (to use a trivial example)

{a, b -> a + b}

{it + 1}