< Paul Woitaschek> `Sequence map map filter map` is just as kotlinlang #announcements

<@U0KBF8D7V> `Sequence.map.map.filter.map` is just...

Andreas Sinz

05/07/2018, 9:54 AM

@Paul Woitaschek

Sequence.map.map.filter.map

is just as fast as

List.forEach { val mapped = ... }

because it "collapses" all operations into one for-loop (no temporary lists) and is even able to short-circuit when possible