The real problem comes when the expression is something like kotlinlang #announcements

The real problem comes when the expression is some...

edwardwongtl

04/26/2018, 5:43 AM

The real problem comes when the expression is something like this

a + b foo 10

becomes

(a + b).bar(10)

, then using the IDE to replace with infix call will become

(a + b) bar 10

, which will retains the bracket.