Or, a bit more efficient: `map2.filterTo(map1.toMu...
# announcementsd
diesieben07
01/15/2018, 10:04 AMOr, a bit more efficient:
map2.filterTo(map1.toMutableMap()) { it.key in map1 }5 Views
diesieben07
01/15/2018, 10:04 AMmap2.filterTo(map1.toMutableMap()) { it.key in map1 }