I ve tried with ``` fun foo synchronized this this being the kotlinlang #announcements

I've tried with ``` fun foo() { synchronized(t...

Fré Dumazy

11/14/2017, 4:01 PM

I've tried with

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fun foo() {
    synchronized(this) { //this being the singleton (object)
       //code
    }
}

Is this different? this approach did not work

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