I also tried `scala Int unbox java lang Integer 1 ` but Inte kotlinlang #announcements

I also tried `scala.Int.unbox(java.lang.Integer(1)...

# announcements

z

zoltu

01/17/2017, 8:25 PM

I also tried

scala.Int.unbox(java.lang.Integer(1))

, but IntelliJ says that expression results in a Kotlin Int.