fellshard
07/20/2016, 6:32 PMoverride fun <List<String>> foo(t: List<String>) {}
, you're trying to override a method named foo
that - when used - binds T
to some type parameter given by the caller of the function. The class itself doesn't care what types the caller wants, and multiple callers can call that same function with different types. E.g.:
val b = B() // Create an instance of B
b.foo(1) // Binds the name Int to type Int
b.foo("bar") // Binds the name Int to type String
All that you've done in B
is rename the type parameter T
to have the name Int
instead.