How about this:
```
val l = listOf("a", "bb", "cc...
# announcementsc
cedric
06/28/2016, 9:16 PMHow about this:
Copy code
val l = listOf("a", "bb", "ccc", "bb", "ccc", "ccc")
l.groupBy { it.length }.map { e -> e.value[0] to e.key }
-> [(a, 1), (bb, 2), (ccc, 3)]