<@U092N7GGG> By "have an expression body" do you m...
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@yole By "have an expression body" do you mean when their assigned to a lambda like this
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fun  foo() = {
            "hello" // return type is inferred as string
        }
Okay, that makes sense. Though I guess I'm still warming up to omitting the return keyword, so I have a small desire to write
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return "hello"
and still be able to infer the return type