mbickel
03/29/2017, 11:56 AM(1, 2, [‘a’]), (2, 3, [‘a’]), (1, 2, [‘b’]) triplets. What I need is (1, 2, [‘a’, ‘b’]), (2, 3, [‘a’]). Is there a idiomatic way to act on the extra elements? I can come up with an ugly way, a nested for loop with a mutable list and some other troubled things but I was looking for a more functional approach.