think of `T ` as a supertype of `T` for any type `T` Therefo kotlinlang #getting-started

think of `T?` as a supertype of `T` for any type `...

okkero

11/29/2016, 1:22 PM

think of

T?

as a supertype of

for any type

Therefore

Any?

is a supertype of

Any

So if the member is defined in

Any

, then it is not reachable through a reference of type

Any?

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