Actually, it's possible to assign `Array<Smth&g...

# getting-started

[ilya.gorbunov]

Actually, it's possible to assign Array<Smth> -> Array<*>, it's not possible to assign Array<Smth<T>> to Array<Smth<*>> because the latter is invariant. And one have to use a covariant projection Array<out Smth<*>> instead to be able to pass Array<Smth<T>> to it.