Can someone explain to me why this work ``` fun foo Observab kotlinlang #getting-started

Can someone explain to me why this work: ``` fu...

mathijs

09/13/2016, 9:01 AM

Can someone explain to me why this work:

Copy code

fun foo(): Observable<StreamItem> {
        return Observable.just(null)
    }

while this gives me an

Type mismatch

error:

Copy code

fun foo(): Observable<StreamItem> {
        val x = Observable.just(null)
        return x
    }

I would think both should error right?!