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<@U1ECL6F8W>: as Ulf already said, `ArrayList<S...
# getting-started
a
Andreas Sinz
06/13/2016, 9:31 AM
@stangls
: as Ulf already said,
ArrayList<String>
would be wrong.
ArrayList.addAll()
expects
Collection<E>
as argument, so you can provide either an
Iterable<String>
or a
ArrayList<String>
, even a
List<String>
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