<@U1ECL6F8W>: as Ulf already said, `ArrayList&lt;S...
# getting-started
a
@stangls: as Ulf already said,
ArrayList<String>
would be wrong.
ArrayList.addAll()
expects
Collection<E>
as argument, so you can provide either an
Iterable<String>
or a
ArrayList<String>
, even a
List<String>