denis.zharkov
10/19/2016, 6:03 PMfun '$'() = 3; $() looks like an issue, but I'm not sure. Please file a report https://youtrack.jetbrains.com/issues
Note that if you add a new line after ; everything works
2. You always can declare it like fun '_'() = 3 and call it with _ name (again from the next line)