So I try to deserialize XML to Kotlin data classes...

# jackson-kotlin

[Stephan Schroeder]

So I try to deserialize XML to Kotlin data classes. The only problem is when a node has attributes and content/text like this logo:

val logo = kotlinXmlMapper.readValue<ImageUrl>(
"""<logo height="50" width="150">https://images.somepage.com/images/logos/150x50/currysnewlogo.gif</logo>"""
)

Here is my data class:

data class ImageUrl(
        val height: Int,
        val width: Int,
        @JacksonXmlText val url: String
)

@JacksonXmlText should be the answer but it’s not:

Caused by: com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Invalid definition for property `` (of type `com.example.demoxmlprocessing.ImageUrl`): Could not find creator property with name '' (known Creator properties: [height, width, url])

my jackson dependencies: (version 2.9.9 is used)

implementation("org.springframework.boot:spring-boot-starter-web-services")
implementation("com.fasterxml.jackson.dataformat:jackson-dataformat-xml")
implementation("com.fasterxml.jackson.module:jackson-module-kotlin")

the mapper definition:

internal val kotlinXmlMapper = XmlMapper(JacksonXmlModule().apply {
    setDefaultUseWrapper(false)
}).registerModule(KotlinModule())
        .configure(MapperFeature.ACCEPT_CASE_INSENSITIVE_PROPERTIES, true)
        .configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)

UPDATE: FIXED IT
I had to specify the name to use for the body text

internal val kotlinXmlMapper = XmlMapper(JacksonXmlModule().apply {
    setDefaultUseWrapper(false)
    setXMLTextElementName("body")
}).registerModule(KotlinModule())
        .configure(MapperFeature.ACCEPT_CASE_INSENSITIVE_PROPERTIES, true)
        .configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)

Now I can map that name to my property:

data class ImageUrl(
        val height: Int,
        val width: Int,
        @JacksonXmlText @JsonProperty("body") val url: String
)