It's a bit tricky I had to do `model.dirtyProperti...

# tornadofx

[thomasnield]

It's a bit tricky I had to do model.dirtyProperties.onChangedObservable().map { it.any { it == model.name } } to determine if a specific property was dirty. Although it wasn't difficult since I obsess over Rx to JavaFX patterns, it might be considered boilerplate by others. I think this was discussed before between you and @Ruckus , but I can't think of a streamlined way to add a "Dirty Property" to a specific Property without inflicting even more overhead on the ViewModel. I guess that's when tools like Rx can come in handy.