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<@U0H8K7DEV> synchronous code cannot call `await()...
# coroutines
p
pniederw
04/04/2017, 5:37 AM
@Ian
synchronous code cannot call
await()
.
future {}
does not silently swallow the exception; the future returned by
future {}
will be completed with an exception. I’m not sure but I think you may have a misunderstanding as to how async works.
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