Yes if inferred type is work for you In this particular case kotlinlang #functional

Yes, if inferred type is work for you In this part...

gildor

07/30/2018, 9:37 AM

Yes, if inferred type is work for you In this particular case

println

returns Unit, so type will be

() -> Unit

, but if last lambda expression returns some other type, infered type will be

() -> LastExpressionType

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