<@U8WU17HH7> `String.format(source, args)` -&gt; `...
# multiplatform
g
@Leonid Popescu
String.format(source, args)
->
String.format(source, *args)
Java String.format uses vararg, so you should pass arguments as vararg, your current code passes array as first argument instead of passing it as varargs
👍 3