`fun <F, A, B> Functor<F>.q(f: (a: A) ...
# arrowp
pakoito
05/23/2019, 2:50 PMfun <F, A, B> Functor<F>.q(f: (a: A) -> B): (fa: F<A>) -> F<B> = { it.map(f) }3 Views
pakoito
05/23/2019, 2:50 PMfun <F, A, B> Functor<F>.q(f: (a: A) -> B): (fa: F<A>) -> F<B> = { it.map(f) }