I have an interface Foo Foo has a self referencing generic t kotlinlang #koin

I have an interface, Foo. Foo has a self-referenci...

forresthopkinsa

04/24/2018, 5:22 PM

I have an interface, Foo. Foo has a self-referencing generic type on its signature, so it looks like

interface Foo<T: Foo<T>>

. Meanwhile, I have another interface,

interface Bar<T : Foo>

. I want to be able to inject an implementation of

Bar

as function in

Foo

so that all of its implementations will reference their type-matching Bar impls. Ehhh I can already tell I'm not making much sense...