Is there an easy way to create a Set<Int> fr...

# getting-started

[Travis Griggs]

Is there an easy way to create a Set<Int> from an OpenEndRange<Int>? I wanted to just do setOf(*(0..<15)) , but the spread operator doesn't like using a Range? (in my case, the range is programatically created, rather than a literal as shown there)

[Klitos Kyriacou]

If it's actually an IntRange you can use range.toSet(). It doesn't work for an OpenEndRange<Int>

[Travis Griggs]

Why is that?

[Shawn]

wait, no

(0..<15).toSet()

works just fine

[Klitos Kyriacou]

Because there's no guarantee that an OpenEndRange<T> contains a finite number of Ts. It does for Int, but that's just a special case. What would you say ("Alpha"..<"Zulu").toSet() should contain?

(0..<15).toSet() works fine because (0..<15) is an IntRange, which implements the OpenEndRange<Int> interface, but importantly it also implements Iterable.

[Travis Griggs]

thanks

[Shawn]

okay, well, when defining a range containing a finite number of elements with a defined ordering, such as Int, like Travis asked, .toSet() works.