Is there an easy way to create a Set<Int> from an OpenEndRange<Int>? I wanted to just do

setOf(*(0..<15))

, but the spread operator doesn't like using a Range? (in my case, the range is programatically created, rather than a literal as shown there)

If it's actually an

IntRange

you can use

range.toSet()

. It doesn't work for an

OpenEndRange<Int>

Why is that?

wait, no

(0..<15).toSet()

works just fine

Because there's no guarantee that an

OpenEndRange<T>

contains a finite number of Ts. It does for

Int

, but that's just a special case. What would you say

("Alpha"..<"Zulu").toSet()

should contain?

(0..<15).toSet()

works fine because

(0..<15)

is an

IntRange

, which implements the

OpenEndRange<Int>

interface, but importantly it also implements

Iterable

.

thanks

okay, well, when defining a range containing a finite number of elements with a defined ordering, such as

Int

, like Travis asked,

.toSet()

works.