Hi, I'm learning a bit ksp and I would like to know how could I pass a file to my

SymbolProcessorProvider

? I tried to pass its relative path as ksp argument like this:

ksp {
    arg("the-file", "src/main/resources/my-file.txt")
}

But then, is there a way to get the root directory of the gradle module which called my ksp processor?

Only way I've found to do this is to burn the file in the processor jar. Example here

Hmmmm, Right now, I have an ugly solution like this

val SymbolProcessorEnvironment.moduleDirectory: File?
    get() {
        codeGenerator.createNewFileByPath(Dependencies(false), "codegen", "txt").close()
        val file = codeGenerator.generatedFile.firstOrNull { it.name == "codegen.txt" } ?: return null

        var counter = 0
        var buildDirectory: File? = null
        var currentDirectory: File? = file

        while(buildDirectory == null && counter < 7 && currentDirectory != null) {
            if(currentDirectory.name == "build") {
                buildDirectory = currentDirectory
            }

            currentDirectory = currentDirectory.parentFile
            counter++
        }

        return buildDirectory?.parentFile
    }

But that´s very sad there is no existing solution 😞

I imagine you'll want to declare the file as an input or output to the ksp task in Gradle so that it can do proper tracking, and then setting the full path as arg shouldn't be much more work than that

This works and gives the right file path:

ksp {
    arg("the-file", project.file("src/main/resources/my-file.txt").path)
}

Gradle won't know to invalidate the task cache when the file changes that way though