Hi, is there a way to open a url on safari?

# compose-ios

[tz311]

Hi, is there a way to open a url on safari?

[Konstantin Tskhovrebov]

fun openUrl(url: String?) {
    val nsUrl = url?.let { NSURL.URLWithString(it) } ?: return
    UIApplication.sharedApplication.openURL(nsUrl)
}

the full example see here: https://terrakok.github.io/Compose-Multiplatform-Wizard/

[tz311]

thank you