Why is this "advice" as a compilation error when a...

# getting-started

[Norbi]

Why is this "advice" as a compilation error when assigning atomic(...) to a local variable (which is later passed to a lambda)?

* Refrain from invoking atomic operations on local variables:

```

val top = atomic<Node?>(null)

val tmp = top

tmp.compareAndSet(null, Node(1)) // DON'T DO THIS

```

Thanks.

[Sam]

AtomicFU works by transforming the code at compile time. An Atomic<T> will actually be transformed into a plain T, and access to it will be turned into direct atomic updates of the underlying field. In other words, at runtime, the Atomic object itself is gone. So you can't pass it around between different variables and functions.

[Norbi]

Hm, thanks.
I thought it will be transformed to AtomicReference , AtomicInteger , etc. 😮

[Sam]

The exact implementation varies by platform, but it's designed to avoid boxing. You can see the details in the docs here. On JVM for example:

an atomic value is represented as a plain value atomically updated with java.util.concurrent.atomic.AtomicXxxFieldUpdater from the Java standard library.

[Sam]

If you want boxed atomics you don't have to use AtomicFU, you can just use AtomicReference instead