I need to escape a path containing non-ascii chara...

# getting-started

[Stefan Oltmann]

I need to escape a path containing non-ascii characters (Unexpected char 0xfc at 11 in Dropbox-API-Arg value: {"path":"/süße vögelchen/photo_9.jpg"}).

In the forums they say this:

For these calls with the parameters in the header, you need to escape these characters. That is, when you use the “Dropbox-API-Arg” header, you need to make it “HTTP header safe”. This means using JSON-style “\uXXXX” escape codes for the character 0x7F and all non-ASCII characters.

Is there anything already build-in to achieve that? Maybe in Ktor or kotlinx-serialization?
How would KMP code look like to do this?

[Stefan Oltmann]

ChatGPT gives me this JVM only code:

fun escapeString(input: String): String {
    val sb = StringBuilder()

    for (char in input) {
        when {
            char == 0x7F.toChar() || char.toInt() > 127 -> {
                // Escape non-ASCII characters using JSON-style "\uXXXX" escape codes
                sb.append("\\u").append(String.format("%04x", char.toInt()))
            }
            else -> sb.append(char)
        }
    }

    return sb.toString()
}

[Sam]

The choice of encoding for header values is really implementation-specific, so I don't think there will be a built-in method that works for exactly this use-case.

[Sam]

JSON strings only need to encode invisible/control characters, so running it through a JSON encoder wouldn't cover all the characters you want to encode.

[Sam]

Technically control characters are the only ones strictly prohibited from HTTP header values too, but implementations are so inconsistent that sticking to plain ASCII is generally safest.

[Stefan Oltmann]

so running it through a JSON encoder wouldn't cover all the characters you want to encode.

Yes, it already runs through kotlinx-serialization, but that doesn't change umlauts. And there seems to be no option to do so.

[Sam]

yeah, there would be no need in ordinary JSON encoding

[Stefan Oltmann]

Okay, understood.

So OkHttp should provide it. At least it's checking for that. There comes the error from.

[Sam]

Well, OkHttp may check for the presence of non-ASCII characters, but that doesn't mean it will provide a way to encode them to ASCII

[Sam]

since the specific encoding method is depending on the API you're using

[Sam]

The ChatGPT suggestion could be reasonably easily modified to pure Kotlin, but it is somewhat incomplete—it fails for non-BMP characters

[Sam]

To write a correct implementation you'd need to iterate the Unicode code points, rather than the 2-byte Java chars, and I don't think pure Kotlin has a way to do that 😞

[Stefan Oltmann]

Damn 😕

[Stefan Oltmann]

ChatGPTs suggestion should be better than the current state

[Sam]

If you're happy with the limitation, you can probably do something like this:

fun escapeString(input: String): String {
  val sb = StringBuilder()
  for (char in input) {
    if (char.code in 32..127) {
      sb.append(char)
    } else {
      sb.append("\\u" + char.code.toHexString().takeLast(4))
    }
  }
  return sb.toString()
}

[Sam]

It will probably fail for characters outside the BMP, unless the receiving server has the same bug in its code 😂 (which is actually not that unlikely, people suck at this stuff)

[Stefan Oltmann]

Indeed, encoding is hard and especially americans tend to forget about the rest of the world 😄

[Stefan Oltmann]

In Germany we only have a few special chars (like our umlauts ä,ö,ü) that also have common representations like ae, oe & ue. So it's usually not to bad. But I know that other countries go crazy with special chars. 😄

[Stefan Oltmann]

I think of France

[Stefan Oltmann]

Your code work! Thank you! 🙂 🙏

[Sam]

Glad I could help!

[Ruckus]

You could make that slightly more idiomatic by using the buildString function:

fun escapeString(input: String) = buildString {
  for (char in input) {
    if (char.code in 32..<127) {
      append(char)
    } else {
      append("\\u" + char.code.toHexString().takeLast(4))
    }
  }
}

Or, if you're feeling really spicy:

fun String.escape() = buildString {
  for (char in this@escape) {
    if (char.code in 32..<127) {
      append(char)
    } else {
      append("\\u" + char.code.toHexString().takeLast(4))
    }
  }
}

(also note I changed it to 32..<127 to match the error, which says 0x7f needs to be converted as well)