In Arrow Optics, how can I create a lens that only focuses of some of the elements in a list that fu...

# arrow

[David]

In Arrow Optics, how can I create a lens that only focuses of some of the elements in a list that fulfil a condition?

Say the following example:

@optics data class Person(val name: String, val age: Int, val friends: List<Person>) {
  companion object
}

Person.friends.every(Every.list()).age.modify(this) { it + 1 }

How can i add a filter on some property, say name starts with x and then modify age with the lens that focus those elements that fulfil the predicate?

[dave08]

I think you can make your own Every.list() that takes a lambda...?

[dave08]

Or just use an if (...) ... else it inside the modify

[David]

Inside the modify, i'm focusing the lens on the property age so I won't have the other properties of the item I'm looking at right?

[dave08]

Yeah, true, I didn't notice you were focusing on something else there...

[David]

I think you can make your own Every.list() that takes a lambda...?

Tried to find this but couldn't 😞

I know I've seen a sample of filtering based on index but not properties 😞

[dave08]

Every.list() is just:

public fun <A> list(): Every<List<A>, A> =
      object : Every<List<A>, A> {
        override fun modify(source: List<A>, map: (focus: A) -> A): List<A> =
          source.map(map)

        override fun <R> foldMap(M: Monoid<R>, source: List<A>, map: (focus: A) -> R): R =
          source.foldMap(M, map)
      }

I think you could add a parameter there that could take a filter and use filter before map or foldMap...?

[dave08]

index will help you to focus on ONE entry, so it might not be what you're looking for here, but I did make one using a lambda once...

[David]

Yeah I've seen findOrNull, but in my case I'd like to find multiple.

[dave08]

This might work:

import arrow.core.foldMap
import arrow.optics.Every
import arrow.typeclasses.Monoid

val list = listOf("one", "two", "two", "three")

fun <A> listFiltered(block: (A) -> Boolean) = object : Every<List<A>, A> {
    override fun modify(source: List<A>, map: (focus: A) -> A): List<A> =
        source.filter(block).map(map)

    override fun <R> foldMap(M: Monoid<R>, source: List<A>, map: (focus: A) -> R): R =
        source.filter(block).foldMap(M, map)
}

println(listFiltered<String> { it == "two" }.modify(list) { "three" })

[dave08]

Nope, it doesn't... it just returns the modified entries... just a second...

[dave08]

This could do it, although I'm not sure about foldMap...:

fun <A> listFiltered(block: (A) -> Boolean) = object : Every<List<A>, A> {
    override fun modify(source: List<A>, map: (focus: A) -> A): List<A> =
        source.map { if (block(it)) map(it) else it }

    override fun <R> foldMap(M: Monoid<R>, source: List<A>, map: (focus: A) -> R): R =
        source.filter(block).foldMap(M, map)
}

[dave08]

@David

[dave08]

Because in foldMap it transforms the result to another type, so you can't just return the old value...

[dave08]

I'm not sure where it's actually used though...

[dave08]

Maybe you don't understand how to use it?

Person.friends.every(listFiltered { it.name ==... }).age.modify(this) { it + 1 }

[Alejandro Serrano.Mena]

In general filtering is not a lens, since it doesn’t allow you to set values back

[dave08]

since it doesn’t allow you to set values back

What do you mean?

[dave08]

Is there any better way to do this then @Alejandro Serrano.Mena?

[dave08]

I've had the same need in the past...

[dave08]

We're still trying to pinpoint on certain values in an immutable structure and modify them... just not all of them.

[Alejandro Serrano.Mena]

The problem is that in order to define a two-way optic, you need to define how to get and how to set elements; but it’s not clear how to do it with filtering

[Alejandro Serrano.Mena]

For example, what if you have a list of numbers, filter to get only the even ones, and then you apply { it + 1 } ?

[dave08]

That's what I wrote above... no?

You mean with that optic I wrote, you can't get the whole set, just the filtered one?

[Alejandro Serrano.Mena]

Yeah, but this would not satisfy the optics laws, so things may behave unexpectedly

[David]

I was away in a meeting. Okay, so this is not really supported then as I understand it? Thanks for then answer @Alejandro Serrano.Mena 🙏