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kotlinlang

what’s currently the best way to open a url in a browser in a compose multiplatform project?

Take a look at the generated project

<https://terrakok.github.io/Compose-Multiplatform-Wizard/|https://terrakok.github.io/Compose-Multiplatform-Wizard/>

wasm:
```window.location.href = url```
android:
```activity.startActivity(
    Intent(Intent.ACTION_VIEW).apply {
        data = Uri.parse(url)
    })```
desktop:
```try {
    Desktop.getDesktop().browse(URI(url))
} catch (e: Exception) {
    println("Failed to open URL: $url with error: ${e.message}")
}```
iOS:
```val nsURL = NSURL.URLWithString(url)
nsURL?.let {
    UIApplication.sharedApplication.openURL(it)
}```


thanks! i also have that expect/actual strategy but was trying to minimize and was hoping for an out-of-the-box solution. the generated project seems cleaner so i’ll take inspiration from that!

You do it in a easier way with Compose

```val uriHandler = LocalUriHandler.current
uriHandler.openUri(
    uri = "link",
)```


It's called to wrap with another layer of abstraction

I don't see a reason to have the handler class here and provide it via a compose state

the handler way does seem easier and still does the job. <@UJ456JG2K> could you tell more about not using the handler class? it seems you are recommending against it but correct me if i misunderstood your statement

Oh! My bad) I haven't known about `androidx.compose.ui.platform.LocalUriHandler` ! I thought <@U04CASA1DT5> says to implement UriHandler by my own