what’s currently the best way to open a url in a browser in a compose multiplatform project?

# compose

[Kurt Renzo Acosta]

what’s currently the best way to open a url in a browser in a compose multiplatform project?

[Konstantin Tskhovrebov]

Take a look at the generated project

https://terrakok.github.io/Compose-Multiplatform-Wizard/

[Rok Oblak]

wasm:

window.location.href = url

android:

activity.startActivity(
    Intent(Intent.ACTION_VIEW).apply {
        data = Uri.parse(url)
    })

desktop:

try {
    Desktop.getDesktop().browse(URI(url))
} catch (e: Exception) {
    println("Failed to open URL: $url with error: ${e.message}")
}

iOS:

val nsURL = NSURL.URLWithString(url)
nsURL?.let {
    UIApplication.sharedApplication.openURL(it)
}

[Kurt Renzo Acosta]

thanks! i also have that expect/actual strategy but was trying to minimize and was hoping for an out-of-the-box solution. the generated project seems cleaner so i’ll take inspiration from that!

[mohamed rejeb]

You do it in a easier way with Compose

val uriHandler = LocalUriHandler.current
uriHandler.openUri(
    uri = "link",
)

[Konstantin Tskhovrebov]

It's called to wrap with another layer of abstraction

[Konstantin Tskhovrebov]

I don't see a reason to have the handler class here and provide it via a compose state

[Kurt Renzo Acosta]

the handler way does seem easier and still does the job. @Konstantin Tskhovrebov could you tell more about not using the handler class? it seems you are recommending against it but correct me if i misunderstood your statement

[Konstantin Tskhovrebov]

Oh! My bad) I haven't known about androidx.compose.ui.platform.LocalUriHandler ! I thought @mohamed rejeb says to implement UriHandler by my own

[Konstantin Tskhovrebov]

I think I will update my wizard 👍

[Konstantin Tskhovrebov]

done