Hey, is it possible for listOf() function somethin...

# getting-started

[Marshall]

Hey, is it possible for listOf() function something like that:

listOf(
     someString1 if someString1 is not null,
     someString2,
     someString3 if someString3 is digits only
)

?

[jamshedalamqaderi]

actually that's not possible. you can do inline if statement but a return is needed for listOf() it would be value or null.

listOf(
    	if(name.contains("J")) name else null,
        if(name.contains("c")) name else null,
    ).filterNotNull()

[Marshall]

OK, thanks

[Gleb Minaev]

listOfNotNull(...) is a bit shorter 🙂

[Marshall]

How that function works? It automatically remove null elements?

[Gleb Minaev]

Yeah. It's the same as listOf(...).filterNotNull().

[Marshall]

@Gleb Minaev Can I call you, if I will have some troubles?

[Marshall]

Because at this moment, I try do some unusual

[Marshall]

But at this moment, it looks like has worked. Thanks

[Gleb Minaev]

@Marshall Sorry, I am a little busy to take calls. You can write me in DM. But there are a lot more people here at #C0B8MA7FA that can help you.

[Marshall]

Sure, no problem, I think, I have solution anyway, so it's OK 🙂

[Johann Pardanaud]

I would rather recommend using buildList in this case:

buildList {
    if (someString1 != null) add(someString1)
    add(someString2)
    if (someString3 != null) add(someString3)
}

[Marshall]

Yeah, Python has some syntax like that

[Daniel Pitts]

buildList the most flexible way to do this.

[Shawn]

listOfNotNull(nullableString, someString2, someString3.takeIf { it.all(Char::isDigit) })

but buildList {} is probably a better option overall

[Daniel Pitts]

If your list can legitimately contain nulls, buildList absolutely is the better option.