I'm confused by this behavior ```sealed interface ...

# getting-started

[y]

I'm confused by this behavior

sealed interface Foo {
    data class FooClass(val n: Int) : Foo {
        fun hello() { /* ... */ }
    }

    data object FooObject : Foo {
        fun hello() { /* ... */ }
    }
}

fun main() {
    val foo = getFoo()
    when (foo) {
        is Foo.FooClass -> foo.hello() // resolves
        Foo.FooObject -> foo.hello() // does not resolve
    }
}

why doesn't this resolve? am I supposed to call it as Foo.FooObject.hello()?

[y]

sorry, copy/paste error

[y]

my apologies

[Joffrey]

Ah I was too late to remove my comment 😅

[y]

NOW it's right heh

[Joffrey]

I believe the check on object without is might not restrict the type itself. Have you tried with is?

[y]

you're right!

[Joffrey]

That being said, you don't really need the foo variable anymore if you already know it's this specific object, so you can indeed simply use the object with Foo.FooObject.hello

[Joffrey]

Also, it might be better to lift the hello declaration up to the Foo interface, so you don't even need a when at all

[y]

so, first of all, I think this behavior is kind of peculiar and I would expect the flow-sensitive typing here to conclude that foo is Foo.FooObject even without the is. the compiler kinda left me in the dark here

as for hoisting the hello to the interface, I wish I could do that but unfortunately the real version of `FooClass`'s hello takes additional context as parameters

[Joffrey]

I see. Yeah I agree that the behavior you're seeing is surprising. It might be worth reporting a YT issue to check if the Kotlin team considers this a bug or not

[y]

I'll see about doing that. thanks again

[Joffrey]

This might be a wider issue than just objects. For instance if the static type is Any and you check for the value 42, we could get flow typing and restrict to Int.

[Joffrey]

Ah I think I understand why we can't restrict the type here. Just because foo is equal to a value doesn't mean that it's of the same type, actually!

[Joffrey]

What if your class FooClass overrides equals and returns true for FooObject values? It would be incorrect to consider that the type is FooObject

[Joffrey]

So if you really want to check on types, you should use is - it's not the same check. It uses instanceof, not equals

[y]

right! I was about to mention how

if (foo == Foo.FooObject) { /* still can't use foo as `FooObject` here */ }

also not working, suggests that this is likely intentional

[y]

yeah. equality is definitely not the same as instanceof
imo the fact that IntellIJ "when branch autofill" assist fills objects as equality checks instead of is checks, also adds to this confusion (it confused me)