This is a doozy..... this works: ``` val x: sus...

# getting-started

[Valeriy O.]

This is a doozy..... this works:

val x: suspend ((String) -> Int) = run {
      { str -> delay(1); str.length }
    }

But adding explicit String type to lambda causes a compilation error:

val x: suspend ((String) -> Int) = run {
      { str: String -> delay(1); str.length }
    }

Type mismatch: 
Required: suspend (String) -> Int
Found: (String) -> Int

Adding suspend doesn't help:

val x: suspend ((String) -> Int) = run {
      suspend { str: String -> delay(1); str.length }
    }

Type mismatch: 
Required: suspend (String) -> Int
Found: suspend () -> Int

Going further with the anonymous lambda syntax doesn't help either...

P.S. Kotlin 2.1.10