what is kts equivalent of `implementation(name: 's...

# gradle

[dawidhyzy]

what is kts equivalent of implementation(name: 'some-library-release', ext: 'aar') ?
I tried implementation(name = "some-library-releasee", ext = "aar") but got

None of the following functions can be called with the arguments supplied: 
public fun <T : Dependency> DependencyHandler.implementation(dependency: TypeVariable(T), action: Action<TypeVariable(T)>): TypeVariable(T) defined in org.gradle.kotlin.dsl
public fun DependencyHandler.implementation(dependencyNotation: Any): Dependency? defined in org.gradle.kotlin.dsl
public fun DependencyHandler.implementation(group: String, name: String, version: String? = ..., configuration: String? = ..., classifier: String? = ..., ext: String? = ..., dependencyConfiguration: Action<ExternalModuleDependency>? = ...): ExternalModuleDependency defined in org.gradle.kotlin.dsl
public fun DependencyHandler.implementation(dependencyNotation: String, dependencyConfiguration: Action<ExternalModuleDependency>): ExternalModuleDependency defined in org.gradle.kotlin.dsl
public fun DependencyHandler.implementation(dependencyNotation: Provider<*>, dependencyConfiguration: Action<ExternalModuleDependency>): Unit defined in org.gradle.kotlin.dsl
public fun DependencyHandler.implementation(dependencyNotation: ProviderConvertible<*>, dependencyConfiguration: Action<ExternalModuleDependency>): Unit defined in org.gradle.kotlin.dsl

[Vampire]

Are you sure that was valid in Groovy?
You miss the group

[Vampire]

It was syntactically valid of course, but I mean did it work properly?

[dawidhyzy]

Yes, it works in groovy

[Vampire]

Well, then use the same method:

implementation(mapOf('name' to 'some-library-release', 'ext' to 'aar'))

But I really wonder what it does without a group.