Using JSON, is there any way to deserialize only k...

# serialization

[Emil Kantis]

Using JSON, is there any way to deserialize only keys of an object into a list? i.e

{
  "foo": { // irrelevant },
  "bar": { // irrelevant },
} -> // [ "foo", "bar ]

Currently I got a

data class Wrapper(
  val entries: Map<String, Irrelevant>
)

But I would like to discard/ignore the values of the map

[Nikky]

if you have it as a JsonObject yu can treat it as a map, so you can just use .keys

so you do not have to declare what structure the irrelevent data is, it just has to be valid json overall

[Nikky]

https://pl.kotl.in/bwlrWEW3f

[Emil Kantis]

Nice, thanks!

[Eugen Martynov]

A bit off topic - you don't convert DTO to domain objects? So just use wrapper.keys after.

[Eugen Martynov]

For me it is more clear than writing a custom json serializer

[Emil Kantis]

It's for _de_serializing in this case.

The API we call returns a json object where we only care about the keys.. I don't want to introduce any data bearer to handle the object values because then I need to make assumptions on how that data will look even though I don't care about it, and that might break deserialization at some point.

[Eugen Martynov]

Just checked code that @Nikky shared and it is a same idea. You parse how it is and extract data you need later.

[Eugen Martynov]

Sorry for jumping on thread and not checking all things

[Nikky]

and that's why we use a JsonObject .. the only assumption we make is that it has keys, the shape of the values are JsonElement, so.. could be any valid structure inside and can be discarded

[Eugen Martynov]

Yeah, could be just Map<String, Any>

[Eugen Martynov]

Ah it is already the original solution

[Nikky]

and that's effectively how JsonObject is defined internally

[Eugen Martynov]

so you made an computed field from it (if I'm correct)

[Nikky]

you could ofc do this more complicated and write a custom deserializer and throw on serialization if you wanna discard the values.. I find that to be too messy