out of curiosity: is there a nice way to abbreviate ```fun foo(): Boolean { val bool = isCondition...

# announcements

[thana]

out of curiosity: is there a nice way to abbreviate

fun foo(): Boolean {
  val bool = isConditionMet()
  if (bool) {
     log(…)
  }
   return bool
}

[Javier]

you can use also for side effects

[thana]

but then again if have to do the if

[thana]

i guess it could to an extension fun Boolean.ifTrue()

[Javier]

fun foo(): Boolean = isConditionMet().also { if (this) log(...) }

You can do a lambda for that, but the code will looks very similar

[thana]

yeah thats hardly shorter and IMHO worse readability 🙂

[dave08]

Make your own alsoIfTrue?

[Javier]

it depends a lot on the eyes that are reading that, if you have the convention to knowing that also is used for side effects, you automatically read it

[thana]

thank you

[Javier]

fun Boolean.ifTrue(block: () -> Unit): Boolean {
    if (this) block()
    return this
}

fun foo(): Boolean = isConditionMet().ifTrue { log(...) }

[Javier]

probably alsoIfTrue is a better name

[CLOVIS]

There's always

fun foo(): Boolean =
  isConditionMet()
  ?.takeIf { it }
  ?.also { log(...) }
  ?: false

but honestly, I don't think it's easier to read.

[Ayfri]

You could also remove the explicit return type