Hi, why can't I use a vararg argument for a typealias of a function ?

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[Ayfri]

Hi, why can't I use a vararg argument for a typealias of a function ?

[Youssef Shoaib [MOD]]

Using an Array<out T> is equivalent to using vararg param: T, and then you can also provide a convenient extension function like this: (playground)

typealias VarargFun<E, R> = (items: Array<out E>) -> R
operator fun <E, R> VarargFun<E, R>.invoke(vararg items: E): R = this(items)

fun testVararg(vararg test: Any?) = listOf(*test)

fun main(){
    var test: VarargFun<Any?, List<Any?>> = ::testVararg
    println(test("hello", "world"))
}

[Ayfri]

Nice it works, thanks !

[turansky]

Strict and without extensions (Kotlin/JS only)