Does anyone know if code like the following: ```inline fun <T> identity(block: () -> T) = b...

# announcements

[Youssef Shoaib [MOD]]

Does anyone know if code like the following:

inline fun <T> identity(block: () -> T) = block
inline fun <T> do(block: () -> T): T = block()
fun main() {
    println(do(identity { "hello" })
}

would be optimised to basically the equivalent of this:

fun main () {
    println("hello")
}

Or would the lambda object still be created because it is being returned by identity? I don't have access to an IDE right this second but this question is burning me so thought I'd ask. If anyone has the time, try pasting this code into a kotlin project then doing Show Kotlin Bytecode then Decompile and look at the Java source code to see what happens.

[nanodeath]

had to rewrite it to this

[nanodeath]

kinda hard to tell but looking at the decompiled code, it doesn't look like it's inlining

[nanodeath]

snippet.kt

snippet.kt

[Youssef Shoaib [MOD]]

Yepppp just like I expected. Thank you so much dude

[Youssef Shoaib [MOD]]

Didn't realise that do was a keyword even huh. That's interesting I guess

[Youssef Shoaib [MOD]]

It's very odd tbh that a case like this isn't inlined when it easily could be since the block never gets used in any non-inlined form

[Youssef Shoaib [MOD]]

Oh wow apparently Kotlin has do while loops. TIL