Another quick question: Is there a way to "unreif...

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[Andrew Adams]

Another quick question:

Is there a way to "unreify" a function call? As in I have a library function that provides a

inline fun <reified T : Any> reifiedFun() {...}

And I have a generic class, which does not allow for reified parameters, and I want to use that library's reified interface

class <A: Any> Test(val javaType: JavaType) {
   fun useIt() {
      // Here is the confusing part
      reifiedFun<A>(javaType); ????
   }
}

[ephemient]

no, it's not possible. ideally the library should expose a generic function plus a reified convenience function

[Andrew Adams]

Ah, actually this library is kotlinx.serialization

[Andrew Adams]

Which I may be missing something then; I'd imagine it would expose a generic function. Particularly for Json.encodeAsString(object)

[Andrew Adams]

I guess encodeToString(serializationStrategy, object) does what I need, thanks!

[Animesh Sahu]

I guess there was a overload which takes a serializer in the first parameter... Oh you already found that 😅