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kotlinlang

is there a way to sort only a ArrayList subrange?

```fun main() {
    val x = mutableListOf(5, 4, 3, 2, 1)
    println(x)
    x.subList(1, 4).sort()
    println(x)
}```
=&gt;
```[5, 4, 3, 2, 1]
[5, 2, 3, 4, 1]```


I thought `subList` copied the list :thinking_face: that's very good to know

from the documentation it looks like there is no copying

<https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.collections/-list/sub-list.html>

Actually <https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.collections/-array-list/sub-list.html> as he asked about `ArrayList`, but it is basically the same, yes. :slightly_smiling_face:

&gt; Returns a *view* of the portion of this list between the specified <https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.collections/-list/sub-list.html#kotlin.collections.List$subList(kotlin.Int,%20kotlin.Int)/fromIndex|fromIndex> (inclusive) and <https://kotlinlang.org/api/latest/jvm/stdlib/kotlin.collections/-list/sub-list.html#kotlin.collections.List$subList(kotlin.Int,%20kotlin.Int)/toIndex|toIndex> (exclusive). *The returned list is backed by this list*, so non-structural *changes* in the returned list *are reflected in this list*, and vice-versa.
&gt; Structural changes in the base list make the behavior of the view undefined.

I think `slice` would give you an independent list

Yes:
```fun main() {
    val x = mutableListOf(5, 4, 3, 2, 1)
    println(x)
    val slice: List&lt;Int&gt; = x.slice(1..3)
    println(slice)
    (slice as MutableList).sort()
    println(slice)
    println(x)
}```
=&gt;
```[5, 4, 3, 2, 1]
[4, 3, 2]
[2, 3, 4]
[5, 4, 3, 2, 1]```