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kotlinlang

```val a = Regex("foo")
a.replace("foobar", "\\w")
res3: kotlin.String = wbar```
i would expect this to return `\\wbar`  - am I missing something here? Isn't `\\` an escape for the `\` ?

this helped me <https://stackoverflow.com/questions/49074632/kotlin-stringreplace-removing-escape-sequences>

Kotlin strings replace `\\` with a single `\` and `\ is special in replacements to quote e.g. the `$` which normally indicates a back reference. So if you welly want `\\bwbar` then you have to use either `Regex("foo").replace("foobar", "\\\\\\\\w")` or `Regex("foo").replace("foobar", """\\\\w""")` (which sidesteps the Kotlin String part)