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kotlinlang

shouldnt postfix `u`  help maybe? (this works though `(0xffff shl 48)`)

Put an L at the end of your 0xfff... number to declare it as a long. But I think it still doesn't fit in a long, does it?

It fits inside unsigned long, which the suffix U should signify, but I think unsigned numbers are still experimental

But you are right, that with signed long, 0xffff... is an overflow

<@U2H3SABQF> If you really need it to be Long, and don't mind that it overflows this would give you what you expect at least as far as bits inside it go
```val l = ((value.toULong() shl 48) and 0xFFFF_0000_0000_0000UL).toLong() ```

This should work as well
```val l = ((value.toLong() and 0xFFFF) shl 48)```