Hi all, I've two infix functions `infix fun Any....

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[PabloCasia]

Hi all,

I've two infix functions

infix fun Any.fun1(block: () -> Unit) = block.invoke()
infix fun Any.fun2(block: () -> Unit) = block.invoke()

And I'm trying to use variables from first fun on second fun, something like:

fun1 { val item1 = "" } fun2 { val item2 = item1 }

But item1 scope is only fun1
Any suggestions? Aware from declare as a lateinit var outside the functions

[jegul]

you can try something like this:
infix fun <T>Any.fun1(block: () -> T) = block.invoke()
infix fun <T>T.fun2(block: T.() -> Unit) = block.invoke(this)

so basically you are returning something from fun1 and use it as receiver to fun2 @PabloCasia

[PabloCasia]

Hi, yes it works but only for one variable and we need to use all the variables inside the fun1

[jegul]

I don’t think it’s possible to use it directly and I don’t actually understand what you are trying to achieve here, but you can workaround it by returning either Pair, Triple, or any other custom data class from fun1, and then use destructuring declarations on fun2.

[karelpeeters]

Alternatively try to move the call to fun2 inside the first block somehow, maybe look into something DSL like?

[streetsofboston]

In your example, you can declare all your val/var outside the calls to fun1 and fun2. (Use so-called 'contracts' to be able to properly use `val`s, declaring that your `block`s are called exactly once).

[PabloCasia]

Thanks, fun2 inside fun1 can be a good solution for me