But we can skip the index if we need?

# announcements

[Kavin]

But we can skip the index if we need?

[Shawn]

return should cause the calling function to return since the lambda isn’t marked as crossinline

[Shawn]

you should be able to return@forEachIndexed

[Shawn]

which will, essentially, break the “loop”

[diesieben07]

It will act like continue, not break.

[Kavin]

But this just skip the index. Like if the condition passes on 5th index and I have return@forEachIndex it just skips the index 5 and continues with the next index i.e, 6th.

[diesieben07]

If you need true break and continue I suggest just using a normal for loop

[diesieben07]

for ((index, value)  in list.withIndex()) {

}

[arekolek]

takeWhile / takeUntil?

[Shawn]

@corneil brings up a good point though - you might be misapplying imperative concepts to a functional construct

[Kavin]

Yeah @diesieben07 is right!

[Kavin]

Yeah I found the alternative ways but just that I wanted to know whether it can be done or not! By the way we can do it by both @corneil and @arekolek ways!