Anyone have any idea why this isn’t working? (`val...

# announcements

[Andrew Gazelka]

Anyone have any idea why this isn’t working? (val people = setOf(personA, personC))

json {
        "test1" to array(personA, personC) //works
        "test2" to array(*people) // does not work
    }

interface KlaxonJson {
fun array(vararg args: Any?) : JsonArray<Any?> = JsonArray(args.map { convert(it) })
// ...

[karelpeeters]

The spread operator * only works on arrays, not sets.

[Toddobryan]

Yeah. So you'd need to .toTypedArray() first.

[karelpeeters]

You'd need that instead.

[Toddobryan]

I meant that you need to call .toTypedArray() before you use the spread operator, but you'd end up with (*people.toTypedArray()) and I think the precedence works out so that the set is converted to an array before the spread operator is applied. (Sorry for using "first" in a horribly ambiguous way.)

[karelpeeters]

Yeah I mean that if you want to convert a set to an array you don't need * and toTypedArray, just the latter will do simple smile

[Hullaballoonatic]

makes me wonder if it would be a good idea to make the spread operator overloadable

[karelpeeters]

https://youtrack.jetbrains.com/issue/KT-12663

[Hullaballoonatic]

yikes, the thought on adding operator fun spread is 3 years old. probably not gonna happen at this point