Is it possible to refactor `fun example(f: (String...

# announcements

[simon.vergauwen]

Is it possible to refactor fun example(f: (String) -> Unit): Unit into fun example(f: (stringParam: String) -> Unit): Unit and refactor all usages of the lambda to use that name in my project?

[Dico]

Extremely unlikely. The parameter name isn't relevant to the code calling example. I believe it is also not retained in binaries at all.

[Dico]

The interface KFunction1 declares the parameter name, it can therefore not technically be different. Parameter names of lambda types might be a future feature, perhaps.

[Dico]

Then the question is, what do you mean by usages? Callers of example or f

[simon.vergauwen]

I thought it was retained in metadata and read from IntelliJ to suggest param names.

[simon.vergauwen]

I mean the callers of f, the reason I want to do this is to improve readability of library code. If I have to do it manually I probably still will but it'll suck

[simon.vergauwen]

If there is another way to achieve the same goal that'd be as good but if so is there a point in naming lambda params from a library point of view?

[Dico]

I dont think theres a point beyond clarity

[Dico]

So the callers of f are all inside the example function right.

[simon.vergauwen]

Oh doy. Of course I meant callers of example so whoever defines parameter names for the lambda. I want example { s ->} to become example { stringParam ->} in my code after the refactor.

[simon.vergauwen]

I dont think theres a point beyond clarity

So no point for a library to do this? Or will IDEA still suggest the param name based on the Metadata?

[Dico]

I can't definitively answer that, but that at least clarifies your question

[simon.vergauwen]

Alright. Thanks for the response 👍